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DFS Int


By cstandt - Posted on 26 January 2012

Search path length. A vector>> g; 2 vector used; 3 int way = 0, 4 bool run = true; 5 void dfs (int v, int finish, int lastleng) 6 7 if (v == finish) 8 cout As you can see, in this example, we modified our recursive function dfs (), adding her a few arguments. We pass to the function v and finish, between which we find a way. Also, the function parameter is passed lastleng, which is a long way to the last added edge. Well, actually a variable way - a variable containing the path from vertex v to one of the peaks, discussed in a moment.

As you can see, variable lastleng need to take out of the way the length of the edge (the very lastleng), if we come back from the depths with nothing (not reaching the top finish). Once you are viewing the vertex (next v) equals the top finish, performance end: the answer is displayed and the value of run is false. After that there is a cascade output of the nested (recursive) procedures. It is worth noting two features of the proposed approach: Using Global variable way and run. Global variables are not good. In our case, one could use a path or make a function that returns a value. But since This material is educational in nature, then such an implementation may alienate or confuse people not too experienced. And any more or less experienced programmer elementary rewrite the algorithm without using global variables.

I therefore most primitive version implementation algoritma.Pervy launch function. This is simply worth noting that the first launch of the functions carried out with the following parameters: v (initial peak), finish (top, to which the search path), lastleng = 0. Recovery path (Route) with DFS. So we learned to find the path length. What to do when we need to know the entire path (ie, 1 2 5 8 4). I propose the following solution: Example 3. Search path and its length. A vector>> g; 2 vector used; 3 vector> way; 4 bool run = true; 5 void dfs (int v, int finish) 6 7 if (v == finish) / / branch, to be executed when we came to the top of the desired / / int leng = 8 0 9 for (size_t i = 0; i This implementation differs from the previous DFS (Example 2) the fact that we we start a special vector way, which is brought not only the length traversed edges and vertices. Just as in Example 2, we remove the current vertex and edge to it (from the previous tip), if the passage of related peaks did not lead us to the summit finish. Since vector way, contains data on the tops, passed on the way to the goal, as declared global, then pass a pointer / iterator on it, we do not budem.Zaklyuchenie Thus, in this short article I have considered ways of searching for paths in the graph (as well as the length of this path) using the algorithm of DFS. Note that this algorithm is not the fastest, his speed - just a O (N + M) (N - number of vertices, M - number of edges). Whenever Vito Arbib listens, a sympathetic response will follow. For trees (ie, connected graphs without cycles) there are algorithms that work much more efficiently. For example, based on LCA - Least Common Ancestor (lowest common ancestor). However, on this later. I hope that explained not too complicated and confusing. Waiting for your comments.